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Academics: Comments, Questions, Suggestions for the Artsci Curriculum
Anyone have poli sci 3LL3 Public policy and development textbook? :)
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Buying Bio2F03 (Ecology) Textbook. Info in chat.
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I am looking for someone to help me in Orgo (chem 2OA3) in first term. If interested, let me know.
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If anyone is interested in taking Indian Religious Traditions (Artsci 3L03) with Dr. Pearson, I've got the course pack from last year and Religions of South Asia. Send me an email.
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Anyone of bio 2ee3 textbooks?
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Who has taken History 2EE3 - Science and technology in world history, who can tell me more about it... i read the review someone wrote, but i was deciding between this one and Relig st 2HH3
ALSO has anyone taken relig st 2ZZ3 - Shakespeare relig and political themes?
thanks :)
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Does anyone know the difference between Artsci 3CG3 and Artsci 3CF3 (the 2 science inquiries...)? Recommend one over the other? thanks :)
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Has anyone taken both Geog 1HA3 or Geog 1HB3 and can someone tell me the difference between the two.
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That is the legal inquiry course indeed. According to Diane's email:
'Arts & Science 3CR3 Topics Inquiry - Legal for 2010-11'
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Question about the new legal inquiry course for next year:
Do we think it's "Inquiry: Special Topics" within the Artsci section on the Master Course Timetable? It says Topic TBA...
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People combining is Psych
Do you recommend 2F03 (Neuroscience with Goldriech) or 2N03 (Principles of Neuropsychology with Ullal)?
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Regarding BIO 2A03
There has been too much bashing of this course. Let it be known that I took this class in winter 2009 and thoroughly enjoyed it (although i went to a total of 4 lectures and had a post-grad TA who just gave us As).
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Any kind souls care to explain A3 and A5 on the 2008/2009 exam?
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Hannah, I like your A8. That totally makes sense!
As for A2)
w=k/m
And you can find k because you know the equilibrium position of the spring. When the spring is at equilibrium,
mg=ks
If you don't understand that, ask me tomorrow and I can show you in person.
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sorry i'm tots stuck on A2a) for 08/09...how did you guys get omega (w)??
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As much as It pains me I have to agree with Daniel for 9. Only part a though. I got 2.44e19 for b.
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8. Ok I did something different again. This time I think I'm right. I got a range for v which I used to get a range for delta p. Then I found the delta x range. Cause the whole point is that we know the velocity range but not the position. I got (3.3133e-35, 3.3127e-35 for the bullet and (7.282e-7,7.281e-7) for the electron. The actual numbers may be off cause I make mistakes a lot but that's what I did. Also I realize the intervals are backwards. I'm a rebel.
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Ok I haven't done most of tehm but so far I agree with everything except 6.
I made a very different assumption thinking that it was excited to n=4. This would allow it to emit 6 differen wavelengths going from 4-3,4-2,4-1,3-2,3-1,2-1. Then I used the same formula. I figured that since that they may not hve necessarily gone to the ground state right away.... Not 100% confident though.
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Whoops, Daniel, you're right about A9. I used mass of the earth instead of the sun.
As for the rest:
2b) If the spring is extended by 0.1m, that means it is 0.14m from the start of the oscillation or 0.06m from the highest point. So, I used 0.06 as my x, and solved for t, then plugged that into the velocity equation.
6) I made that same assumption, but I calculated the energy change to promote and electron from n=1 to n=7. Then I subbed that into E=hc/lambda.
8) Isn't the equation delta p delta x > h(bar)/2? Also, I don't know why you did the 1% range thing. It might be right, I just have no idea why you would do it.
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Upon closer inspection I am wear loafers.
Thanks Carla.
2b) can you go over how you got this, i get .75 m/s but i'm not that happy with it.
5) carla is correct, calculation error on my part.
6) my revised, but likely inaccurate solution is 9.3e-8. I simple assumed that the beam had excited hydrogen to its 7th energy level, thus allowing it to emmit 7 different spectrums as it jumped down each energy level. then used the 1/lambda = R (1/n^2 - 1/m^2) to find the wavelength of the light.
8) so i used delta p x delta x > h. we know both m and v, so can solve for selta p (i think). and then calculate x, i simple added and subtracted 0.01 of my answer for x to get a range, probably not right, but thats whati got.
9) i kinda stand by my answers. i used Rs=2GM/c^2, to find r, what did you do.
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